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4.905x^2-2.74-12=0
We add all the numbers together, and all the variables
4.905x^2-14.74=0
a = 4.905; b = 0; c = -14.74;
Δ = b2-4ac
Δ = 02-4·4.905·(-14.74)
Δ = 289.1988
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{289.1988}}{2*4.905}=\frac{0-\sqrt{289.1988}}{9.81} =-\frac{\sqrt{}}{9.81} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{289.1988}}{2*4.905}=\frac{0+\sqrt{289.1988}}{9.81} =\frac{\sqrt{}}{9.81} $
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